Think about this incredible value (last yr and this yr)

Axis · Apr 28, 2007

BonScott said: ↑

Great moves by Tanny. 2 instant starters. I wonder if Tanny suggested similar moves to Bradway in the past only to get shot down.
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It's very possible.

At least now we don't have to worry about that happening. The jets have a great future ahead of them, I think.

RobA · Apr 28, 2007

We definitely didn't give up too much, I love the trade, addressing a huge need in a CB. Revis will be our starter for years to come, and with dyson, rhodes, and coleman, our secondary is dangerous. Plus lots of depth in miller, eric smith, etc.

dclark26 · Apr 28, 2007

NJJets said: ↑

Suppose z = x + iy for real variables x and y. Then we can write x = (z + \bar z)/2 and y = (z - \bar z)/(2i). Now x and y can be thought of as real functions of complex variables z and \bar z. Differentiating x and y gives:

{\partial x \over \partial z} = {1 \over 2}\ \mathrm{and}\ {\partial y \over \partial z} = {1 \over 2i}

as well as

{\partial x \over \partial \bar z} = {1 \over 2}\ \mathrm{and}\ {\partial y \over \partial \bar z} = -{1 \over 2i}.

Differentiate a function f(x,y) = u(x,y) + iv(x,y):

{\partial f \over \partial z} = {\partial f \over \partial x}{\partial x \over \partial z} + {\partial f \over \partial y}{\partial y \over \partial z}\ \mathrm{and}\ {\partial f \over \partial \bar z} = {\partial f \over \partial x}{\partial x \over \partial \bar z} + {\partial f \over \partial y}{\partial y \over \partial \bar z}.

Finally, substitution yields:

{\partial f \over \partial z} = {1 \over 2}\left({\partial f \over \partial x} + {1 \over i}{\partial f \over \partial y}\right)\ \mathrm{and}\ {\partial f \over \partial \bar z} = {1 \over 2}\left({\partial f \over \partial x} - {1 \over i}{\partial f \over \partial y}\right).

If we let {\partial f \over \partial \bar z} = 0, then {\partial f \over \partial x} = -i {\partial f \over \partial y} and thus

{\partial u \over \partial x} + i{\partial v \over \partial x} = -i\left({\partial u \over \partial y} + i{\partial v \over \partial y}\right),
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or you could have just written 2+2=4.

Think about this incredible value (last yr and this yr)

Axis New Member

RobA 2005-2007 TGG.com Most Optimistic Award Winner

dclark26 New Member

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Think about this incredible value (last yr and this yr)

Axis New Member

RobA 2005-2007 TGG.com Most Optimistic Award Winner

dclark26 New Member

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